An object is placed 25 cm in front of a lens of focal length 20 cm.60 cm past the first lens is a second lens of focal length 25 cm.What is the resulting magnification of the object in this setup?
A) $- 1.6$
B) $+ 8.0$
C) $- 8.0$
D) $+ 1.4$
E) $- 1.2$

Question

Quizplus · Accepted Answer

The magnification of the first lens is $-1$ (using $m_1 = -\frac{v_1}{u_1}$), and the magnification of the second lens is $-1.6$ (using $m_2 = -\frac{v_2}{u_2}$). The total magnification is the product of the two, $-1 \times -1.6 = -1.6$.

An Object Is Placed 25 Cm in Front of a Lens