A weather balloon contains 12.0 m³ of hydrogen gas when the balloon is released from a location at which the temperature is 22.0°C and the pressure is 101 kPa. The balloon rises to a location where the temperature is -30.0°C and the pressure is 20.0 kPa. If the balloon is free to expand so that the pressure of the gas inside is equal to the ambient pressure, what is the new volume of the balloon? Assume that in both cases the hydrogen gas is in thermal equilibrium with the outside air. A) 14.0 m³ B) 2.38 m³ C) 49.9 m³ D) 82.6 m³ E) 4.16 m³

Question

Quizplus · Accepted Answer

Using the ideal gas law and the combined gas law, the new volume can be calculated as follows: V2 = V1 * (P1/P2) * (T2/T1). Converting temperatures to Kelvin and substituting the given values, V2 = 12.0 m³ * (101 kPa / 20 kPa) * (243 K / 295 K) = 49.9 m³.

A Weather Balloon Contains 12