A 0.600-mm diameter wire stretches 0.500% of its length when it is stretched with a tension of 20.0 N. What is the Young's modulus of this wire? A) 5.66 × 1010 N/m² B) 3.54 × 109 N/m² C) 1.41 × 1010 N/m² D) 6.43 × 109 N/m² E) 2.78 × 109 N/m²

Question

Quizplus · Accepted Answer

We can use the formula for Young's modulus:
Y = (F/A) / (ΔL/L)
where F is the applied force, A is the cross-sectional area of the wire, ΔL is the change in length, and L is the original length.

We first need to find the cross-sectional area of the wire:
A = πr^2 = π(0.0003m/2)^2 = 7.07×10^-8m^2

Next, we can use the given values to solve for Y:
Y = (20N/7.07×10^-8m^2) / (0.005 * 1.000) = 1.41 × 10^10 N/m^2

Therefore, the best choice is C.

A 0600-Mm Diameter Wire Stretches 0