A box of 11 transistors has 7 defective ones. If 2 transistors are drawn from the box together, what is the probability that both transistors are defective? Round your answer to two decimal places.

Question

A box of 11 transistors has 7 defective ones. If 2 transistors are drawn from the box together, what is the probability that both transistors are defective? Round your answer to two decimal places. ​

Quizplus · Accepted Answer

The probability of drawing a defective transistor on the first attempt is 7/11.
After drawing one defective transistor, there will be 6 defective transistors left out of 10 transistors total.
Thus, the probability of drawing another defective transistor on the second attempt is 6/10.
Using the multiplication rule of probability, the probability of drawing 2 defective transistors in sequence is (7/11) * (6/10) = 0.38 which rounded to two decimal places is 0.38.
Therefore, the best choice is B.

A Box of 11 Transistors Has 7 Defective Ones