If 5% of all light bulbs a company manufactures are defective, the probability of any one bulb being defective is 0.05. What is the probability that two bulbs drawn independently from the company's stock will be defective? Round your answer to eight decimal places.
A) 0.25000000
B) 0.00012500
C) 0.05000000
D) 0.00250000
E) 0.00000000

Question

If 5% of all light bulbs a company manufactures are defective, the probability of any one bulb being defective is 0.05. What is the probability that two bulbs drawn independently from the company's stock will be defective? Round your answer to eight decimal places. ​
A) 0.25000000
B) 0.00012500
C) 0.05000000
D) 0.00250000
E) 0.00000000

Quizplus · Accepted Answer

The probability of drawing two defective bulbs can be calculated using the formula for independent events:

P(A and B) = P(A) x P(B)

where A and B are the events of drawing a defective bulb.

Therefore:

P(two defective bulbs) = P(A and B) 
= P(A) x P(B) 
= 0.05 x 0.05 
= 0.0025

Rounding to eight decimal places gives us 0.00250000, which matches choice D.

If 5% of All Light Bulbs a Company Manufactures Are