Suppose a fair coin is tossed 6 times. What is the probability of flipping exactly 2 heads?
A) Pr(2 heads) =
B) Pr(2 heads) =
C) Pr(2 heads) =
D) Pr(2 heads) =
E) Pr(2 heads) =

Question

Suppose a fair coin is tossed 6 times. What is the probability of flipping exactly 2 heads? ​
A) Pr(2 heads) = 
B) Pr(2 heads) = 
C) Pr(2 heads) = 
D) Pr(2 heads) = 
E) Pr(2 heads) =

Quizplus · Accepted Answer

The probability of flipping exactly two heads in six fair coin tosses can be calculated using the binomial probability formula.

Pr(2 heads) = (6 choose 2) * (1/2)^2 * (1/2)^4

where (6 choose 2) is the number of ways to choose 2 heads out of 6 total tosses, and (1/2)^2 * (1/2)^4 represents the probability of getting 2 heads and 4 tails.

Evaluating this expression, we get:

Pr(2 heads) = (6 choose 2) * (1/2)^2 * (1/2)^4 
= (15) * (1/4) * (1/16) 
= 15/64

So the probability of flipping exactly 2 heads is 15/64, which matches choice C.

Suppose a Fair Coin Is Tossed 6 Times