Suppose a report by U.S. News and World Report states that 25% of all employee credentials examined were falsified. If this is true, what is the probability that at least 79 of 240 employees hired during a year had falsified their credentials? Round your answer to four decimal places.
A)0.2594
B)0.9971
C)0.0029
D)0.0366
E)0.0042

Question

Suppose a report by U.S. News and World Report states that 25% of all employee credentials examined were falsified. If this is true, what is the probability that at least 79 of 240 employees hired during a year had falsified their credentials? Round your answer to four decimal places. ​
A)​0.2594
B)​0.9971
C)​0.0029
D)​0.0366
E)​0.0042

Quizplus · Accepted Answer

This situation follows a binomial distribution with n = 240 and p = 0.25. We want to find the probability that at least 79 employees out of 240 had falsified credentials, which can be represented as P(X ≥ 79), where X is the number of employees with falsified credentials. Using a binomial calculator or software, we calculate P(X ≥ 79) to be approximately 0.0029. Therefore, the best choice is C.

Suppose a Report by U