Suppose the Circuitown buys plasma televisions in sets of 1500. If a television is defective with probability 0.01, what is the probability that at least 24 televisions will be defective in a set? Round your answer to four decimal places.
A)0.9864
B)0.0136
C)0.8821
D)0.7496
E)0.809

Question

Suppose the Circuitown buys plasma televisions in sets of 1500. If a television is defective with probability 0.01, what is the probability that at least 24 televisions will be defective in a set? Round your answer to four decimal places. ​
A)0.9864
B)0.0136
C)0.8821
D)0.7496
E)0.809

Quizplus · Accepted Answer

The problem can be modeled using a binomial distribution with n = 1500 and p = 0.01. To find the probability that at least 24 televisions are defective, we calculate P(X ≥ 24). This can be approximated using a normal distribution due to the large n, where the mean μ = np = 15 and the standard deviation σ = √(np(1-p)) ≈ 3.87. Using the normal approximation, we find P(X ≥ 24) ≈ 0.0136.

Suppose the Circuitown Buys Plasma Televisions in Sets of 1500