If (x,y) is a point on the parabola y = 3 $x ^ { 2 }$ , then the tangent line to y = 3 $x ^ { 2 }$ passing through (x,y) has slope 6x. Find the equation of the line tangent to y = 3 $x ^ { 2 }$ through the point (-2, 12).
A) y = 6x + 12
B) y = 12x + 6
C) y = -12x - 12
D) y = -2x + 12

Question

Quizplus · Accepted Answer

The slope of the tangent line at (-2, 12) is 6(-2) = -12. Using the point-slope form, the equation is y - 12 = -12(x + 2), which simplifies to y = -12x - 12.

If (X,y) Is a Point on the Parabola Y = x2x ^ { 2 }x2

If (X,y) Is a Point on the Parabola Y = $x ^ { 2 }$