Given the differential equation: $y ^ { \prime } = y ^ { 2 } - t ^ { 2 } y ^ { 2 }$ , is this the solution: $y = \frac { 1 } { \frac { 1 } { 3 } t ^ { 3 } - t + C } ?$

Name: Given the differential equation: $y ^ { \prime } = y ^ { 2 } - t ^ { 2 } y ^ { 2 }$ , is this the solution: $y = \frac { 1 } { \frac { 1 } { 3 } t ^ { 3 } - t + C } ?$
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Question

Quizplus · Accepted Answer

The given solution satisfies the differential equation when substituted back, as it simplifies to the original equation.

Given the Differential Equation y′=y2−t2y2y ^ { \prime } = y ^ { 2 } - t ^ { 2 } y ^ { 2 }y′=y2−t2y2

Given the Differential Equation $y ^ { \prime } = y ^ { 2 } - t ^ { 2 } y ^ { 2 }$