Suppose the second Taylor polynomial for f(x) at x = 3 is $P 2 ( x ) = 2 ( x - 3 ) - \frac { 1 } { 3 } ( x - 3 ) ^ { 2 }$ . Find f''(3).
Enter just a reduced fraction.

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The Answer of Suppose the second Taylor polynomial for f(x) at x = 3 is $P 2 ( x ) = 2 ( x - 3 ) - \frac { 1 } { 3 } ( x - 3 ) ^ { 2 }$ . Find f''(3).
Enter just a reduced fraction.

Suppose the Second Taylor Polynomial for F(x) at X = P2(x)=2(x−3)−13(x−3)2P 2 ( x ) = 2 ( x - 3 ) - \frac { 1 } { 3 } ( x - 3 ) ^ { 2 }P2(x)=2(x−3)−31​(x−3)2

Suppose the Second Taylor Polynomial for F(x) at X = $P 2 ( x ) = 2 ( x - 3 ) - \frac { 1 } { 3 } ( x - 3 ) ^ { 2 }$