A basketball player attempts successive free throws until he succeeds in making a basket. Suppose the probability of success of each attempt is 0.7; thus, the probability of exactly n failures before the first success is $( 0.3 ) ^ { n }$ (0.7), n ≥ 0. What is the probability that the number of failures before the first successful free throw is odd? Enter just a reduced fraction.

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The Answer of A basketball player attempts successive free throws until he succeeds in making a basket. Suppose the probability of success of each attempt is 0.7; thus, the probability of exactly n failures before the first success is $( 0.3 ) ^ { n }$ (0.7), n ≥ 0. What is the probability that the number of failures before the first successful free throw is odd? Enter just a reduced fraction.

A Basketball Player Attempts Successive Free Throws Until He Succeeds (0.3)n( 0.3 ) ^ { n }(0.3)n

A Basketball Player Attempts Successive Free Throws Until He Succeeds $( 0.3 ) ^ { n }$