Simplify.
-$e ^ { 2 } \ln 5$ + ln( $e ^ { x }$ ∙ $\mathrm { e } ^ { 4 }$ )
A) 10 + x ∙ $\mathrm { e } ^ { 4 }$
B) 29 + x
C) 25 + 4x
D) 10 + 4x

Question

Quizplus · Accepted Answer

The expression simplifies using properties of logarithms and exponents. $e^2 \ln 5$ simplifies to $5^2 = 25$ because $e^{\ln x} = x$. The second term, ln($e^x \cdot e^4$), simplifies to $x + 4$ because ln and e are inverse functions and the property of logarithms that ln(ab) = ln(a) + ln(b) applies. Adding these together gives $25 + x + 4 = 29 + x$.

Simplify - e2ln⁡5e ^ { 2 } \ln 5e2ln5 + Ln exe ^ { x }ex

Simplify
- $e ^ { 2 } \ln 5$ + Ln $e ^ { x }$