In the Figure Below, the Region Enclosed by the Curves $\frac { 4 } { x }$

In the figure below, the region enclosed by the curves y = - $\frac { 4 } { x }$ , y = -x, and y = -x + 3 is shown. Set up an integral or sum of integrals to find the area of the shaded region. (Do not calculate the area.)

A) $\int _ { - 2 } ^ { - 1 } \left( - \frac { 4 } { x } + x \right) d x$ + $\int _ { - 1 } ^ { 2 } 3 d x$ + $\int _ { 2 } ^ { 4 } \left( - x + 3 + \frac { 4 } { x } \right) d x$
B) $\int _ { - 2 } ^ { 2 } 3 \mathrm { dx } \int _ { 2 } ^ { 4 } \left( - x + 3 - \frac { 4 } { x } \right) \mathrm { dx }$
C) $\int _ { - 2 } ^ { 0 } \left( - \frac { 4 } { x } + x \right) d x$ + $\int _ { 0 } ^ { 2 } \left( - x + 3 + \frac { 4 } { x } \right) d x$
D) $\int _ { - 2 } ^ { 4 } 3 d x$
E) none of these