Approximate the area of a parallelogram that has sides of lengths a and b (in feet) if one angle at a vertex has measure $\theta$ . $a = 9.0 , b = 16.0$ $\theta = 40 ^ { \circ }$
A) 95.2
B) 110.3
C) 89.3
D) 88.4
E) 92.6

Question

Quizplus · Accepted Answer

The area of a parallelogram is given by $ A = ab \sin(\theta) $. Substituting the given values: $ A = 9.0 \times 16.0 \times \sin(40^\circ) \approx 92.6 $.

Approximate the Area of a Parallelogram That Has Sides of Lengths