The matrices A and B are defined as follows: A = $\left( \begin{array} { r r }
4 & 5 \
- 1 & 6
\end{array} \right)$ , B = $\left( \begin{array} { r r }
1 & - 1 \
2 & 0
\end{array} \right)$ Carry out the indicated matrix operation. $A B$
A) $\left( \begin{array} { c c }
14 & - 4 \
11 & 13
\end{array} \right)$
B) $\left( \begin{array} { c c }
14 & - 4 \
11 & 1
\end{array} \right)$
C) $\left( \begin{array} { r r }
4 & - 13 \
11 & 1
\end{array} \right)$
D) $\left( \begin{array} { c c }
12 & - 4 \
11 & 13
\end{array} \right)$
E) $\text { not defined }$

Question

The matrices A and B are defined as follows: A = $\left( \begin{array} { r r } 
4 & 5 \
- 1 & 6
\end{array} \right)$ , B = $\left( \begin{array} { r r } 
1 & - 1 \
2 & 0
\end{array} \right)$ Carry out the indicated matrix operation. $A B$
A) $\left( \begin{array} { c c } 
14 & - 4 \
11 & 13
\end{array} \right)$
B) $\left( \begin{array} { c c } 
14 & - 4 \
11 & 1
\end{array} \right)$
C) $\left( \begin{array} { r r } 
4 & - 13 \
11 & 1
\end{array} \right)$
D) $\left( \begin{array} { c c } 
12 & - 4 \
11 & 13
\end{array} \right)$
E) $\text { not defined }$

Quizplus · Accepted Answer

The product of matrices A and B is calculated as follows:  First row, first column: $4*1 + 5*2 = 14$  First row, second column: $4*(-1) + 5*0 = -4$  Second row, first column: $-1*1 + 6*2 = 11$  Second row, second column: $-1*(-1) + 6*0 = 1$  Thus, the resulting matrix is $\left( \begin{array} { c c } 14 & -4 \ 11 & 1 \end{array} \right)$.

The Matrices a and B Are Defined as Follows: a =