A student in a chemistry laboratory has access to two acid solutions. The first solution is $10 \%$ acid and the second is $35 \%$ acid. (The percentages are by volume.) How many cubic centimeters of each should she mix together to obtain $150 \mathrm {~cm} ^ { 3 }$ of a $25 \%$ acid solution?
A) $60 \mathrm { cc } \text { of } 10 \% \text { solution and } 102 \mathrm { cc } \text { of } 35 \% \text { solution }$
B) $50 \mathrm { cc } \text { of } 10 \% \text { solution and } 90 \mathrm { cc } \text { of } 35 \% \text { solution }$
C) $90 \mathrm { cc } \text { of } 10 \% \text { solution and } 60 \mathrm { cc } \text { of } 35 \% \text { solution }$
D) $60 \mathrm { cc } \text { of } 10 \% \text { solution and } 90 \mathrm { cc } \text { of } 35 \% \text { solution }$
E) $60 \mathrm { cc } \text { of } 10 \% \text { solution and } 100 \mathrm { cc } \text { of } 35 \% \text { solution }$

Question

Quizplus · Accepted Answer

To obtain a 25% acid solution from a mix of 10% and 35% solutions, we can use the equation $0.10x + 0.35y = 0.25(150)$, where $x$ and $y$ are the volumes of the 10% and 35% solutions, respectively. Additionally, $x + y = 150$. Solving these equations simultaneously, we find that $x = 60$ and $y = 90$, which corresponds to choice D.

A Student in a Chemistry Laboratory Has Access to Two 10%10 \%10%

A Student in a Chemistry Laboratory Has Access to Two $10 \%$