A university found it retained 25 students out of 352 in 2012 and 36 students out of 334 in 2013.
A)P-value = 0.0455; If there is no difference in the proportions,there is about a 4.55% chance of seeing the observed difference or larger by natural sampling variation.
B)P-value = 0.9545; If there is no difference in the proportions,there is about a 95.45% chance of seeing the observed difference or larger by natural sampling variation.
C)P-value = 0.0455; There is about a 4.55% chance that the two proportions are equal.
D)P-value = 0.091; There is about a 9.1% chance that the two proportions are equal.
E)P-value = 0.091; If there is no difference in the proportions,there is about a 9.1% chance of seeing the observed difference or larger by natural sampling variation.

Question

Quizplus · Accepted Answer

The p-value of 0.091 indicates that there is a 9.1% chance of observing the difference in retention rates or a more extreme difference purely due to random sampling variation, assuming there is no actual difference in the proportions.

A University Found It Retained 25 Students Out of 352