The following ANOVA table shows the results of an experiment used to test scores for males and females at 4 different times of day.Assuming no effect from the interaction between gender and test time,test the claim that males and females perform the same on the test. $$\begin{array}{l}
\begin{array} { l c c c c r }
&&\text { Sum of}&{ Mean }\
\text { Source } & \text { DF } & \text { Squares } & \text { Square } & \text { F-ratio } & \text { P-value } \
\text { Gender } & 1 & 24.5 & 24.5 & 0.6652 & 0.4745 \
\text { Time } & 3 & 183 & 61 & 1.6561 & 0.3444 \
\text { Error } & 3 & 110.5 & 36.83 & & \
\text { Total } & 7 & 318 & & &
\end{array}
\end{array}$$

Question

The following ANOVA table shows the results of an experiment used to test scores for males and females at 4 different times of day.Assuming no effect from the interaction between gender and test time,test the claim that males and females perform the same on the test. $$\begin{array}{l}
\begin{array} { l c c c c r } 
&&\text { Sum of}&{ Mean }\
\text { Source } & \text { DF } & \text { Squares } & \text { Square } & \text { F-ratio } & \text { P-value } \
\text { Gender } & 1 & 24.5 & 24.5 & 0.6652 & 0.4745 \
\text { Time } & 3 & 183 & 61 & 1.6561 & 0.3444 \
\text { Error } & 3 & 110.5 & 36.83 & & \
\text { Total } & 7 & 318 & & &
\end{array}
\end{array}$$

Quizplus · Accepted Answer

The Answer is H0: γ1 = γ2,where γ represents the effect of gender vs.HA: Both genders do not have the same effect.The null hypothesis states that gender has no effect on test score.The alternative states that it does.The P-value for gender is 0.4745,which provides insufficient evidence to indicate that gender had an effect on the mean score.

The Following ANOVA Table Shows the Results of an Experiment