A refrigerator with a COP of 3.7 cools to 9.0°C.What is the high temperature,T_h,needed to operate the refrigerator at 9.0°C? A)85°C B)1052°C C)11°C D)42°C

Question

Quizplus · Accepted Answer

The COP of a refrigerator is given by the ratio of the heat removed from the cold reservoir to the work done. In this case, the COP is 3.7 and the temperature of the cold reservoir is 9.0°C. We can use the following equation to find the temperature of the hot reservoir:COP = Qc / W = Th / (Th - Tc)where Qc is the heat removed from the cold reservoir, W is the work done, Th is the temperature of the hot reservoir, and Tc is the temperature of the cold reservoir.Solving for Th, we get:Th = COP * (Th - Tc) / TcSubstituting the given values, we get:Th = 3.7 * (Th - 9.0°C) / 9.0°CTh = 3.7 * Th - 33.3°C4.7 * Th = 33.3°CTh = 33.3°C / 4.7Th = 7.08°CTherefore, the high temperature needed to operate the refrigerator at 9.0°C is 7.08°C.

A Refrigerator with a COP of 3