A 0.588 m string is clamped at both ends.If the lowest standing wave frequency in the string is 326 Hz,what is the wave speed?
A)383 m/s
B)475 m/s
C)582 m/s
D)724 m/s

Question

Quizplus · Accepted Answer

The lowest standing wave frequency in a string clamped at both ends is given by:$$f_1 = \frac{v}{2L}$$where:* f_1 is the lowest standing wave frequency* v is the wave speed* L is the length of the stringSolving for v, we get:$$v = 2f_1L$$Substituting the given values, we get:$$v = 2(326 	ext{ Hz})(0.588 	ext{ m}) = 383 	ext{ m/s}$$Therefore, the wave speed is 383 m/s, which corresponds to choice A.

A 0588 M String Is Clamped at Both Ends