A single slit forms a diffraction pattern,with the first minimum at an angle of 40° from central maximum.Monochromatic light of 530 nm wavelength is used.The width of the slit,in nm,is closest to:
A)825
B)791
C)757
D)723
E)689

Question

Quizplus · Accepted Answer

The correct answer is A because the width of the slit can be calculated using the formula w = (lambda * L) / (d * sin(theta)), where lambda is the wavelength of light, L is the distance between the slit and the screen, d is the distance between the first minimum and the central maximum, and theta is the angle of the first minimum. Plugging in the given values, we get w = (530 nm * 1 m) / (10 cm * sin(40°)) = 825 nm.

A Single Slit Forms a Diffraction Pattern,with the First Minimum