An electron enters a magnetic field of 0.75 T with a velocity perpendicular to the direction of the field.At what frequency does the electron traverse a circular path? (The mass of an electron is 9.1 × 10^-31 kg,and the charge of an electron is 1.6 × 10^-19C. ) A)2.1 × 10¹⁰ Hz B)4.8 × 10^-7 Hz C)2.1 × 10¹⁴Hz D)4.8 × 10^-11Hz

Question

Quizplus · Accepted Answer

The frequency of circular motion is given by:

f = (qB)/(2πm)

where q is the charge of the particle, B is the magnetic field strength, and m is the mass of the particle.

Plugging in the values for the electron:

q = 1.6 × 10^-19 C
B = 0.75 T
m = 9.1 × 10^-31 kg

f = (1.6 × 10^-19 C × 0.75 T)/(2π × 9.1 × 10^-31 kg)

f = 2.1 × 10^10 Hz

Therefore, the electron traverses a circular path at a frequency of 2.1 × 10^10 Hz, which corresponds to answer choice A.

An Electron Enters a Magnetic Field of 0