An electron moves with a horizontal velocity of 3.0 × 10⁶ m/s as it enters a deflector inside a TV tube.The electron strikes the screen after traveling 17.0 cm horizontally and 40.0 cm vertically upward.What is the constant vertical acceleration provided by the deflector? A)2.5 × 10¹⁴ m/s² B)8.3 × 10² m/s² C)1.4 × 10⁴ m/s² D)1.2 × 10¹⁴ m/s²

Question

Quizplus · Accepted Answer

The correct answer is A because the vertical acceleration can be calculated using the formula: a = (vf^2 - vi^2) / 2d, where vf is the final vertical velocity, vi is the initial vertical velocity, and d is the vertical displacement. Plugging in the given values, we get: a = (0^2 - (3.0 × 10^6 m/s)^2) / 2(0.40 m) = 2.5 × 10^14 m/s^2.

An Electron Moves with a Horizontal Velocity of 3