Jeff ran up the hill at 7.0 m/s.The horizontal component of Jeff's velocity vector was 5.1 m/s.What was the vertical component of Jeff's velocity?
A)4.8 m/s
B)4.3 m/s
C)3.8 m/s
D)3.4 m/s

Question

Quizplus · Accepted Answer

The vertical component of Jeff's velocity can be found using the Pythagorean theorem:```v_vertical^2 = v_total^2 - v_horizontal^2```where:* v_vertical is the vertical component of Jeff's velocity* v_total is the total velocity of Jeff* v_horizontal is the horizontal component of Jeff's velocityPlugging in the given values, we get:```v_vertical^2 = 7.0^2 - 5.1^2v_vertical^2 = 49 - 26.01v_vertical^2 = 22.99v_vertical = sqrt(22.99)v_vertical = 4.8 m/s```Therefore, the vertical component of Jeff's velocity is 4.8 m/s.

Jeff Ran Up the Hill at 7