A force of 16.88 N is applied tangentially to a wheel of radius 0.340 m and gives rise to an angular acceleration of 1.20 rad/s².Calculate the rotational inertia of the wheel. A)4.78 kg ∙ m² B)3.59 kg ∙ m² C)5.98 kg ∙ m² D)7.17 kg ∙ m²

Question

Quizplus · Accepted Answer

The torque τ is given by τ = r * F = 0.340 m * 16.88 N = 5.7392 N∙m. The rotational inertia I is given by τ = I * α, so I = τ / α = 5.7392 N∙m / 1.20 rad/s² = 4.7827 kg∙m², which is approximately 4.78 kg∙m².

A Force of 16