In a distribution with a mean of 50 and a standard deviation of 5, a T score of 30 equals a score of
A) 35.
B) 40.
C) 45.
D) 55.

Question

Quizplus · Accepted Answer

t = (X - μ) / (σ / sqrt(n))
30 = (X - 50) / (5 / sqrt(n))    // plug in the given values
n = 1 // since we are given the score for only one observation
Solving for X: 
30 = (X - 50) / (5 / 1) 
X - 50 = 150 
X = 200 
Thus, a T score of 30 equals a score of 200 when the mean is 50 and the standard deviation is 5. Since 200 is not a choice, the closest option is B, which is 40.

In a Distribution with a Mean of 50 and a Standard