What is the molality of a solution prepared by dissolving 86.9 g of diethyl ether, C₄H₁₀O, in 425 g of benzene, C₆H₆? A) 0.362 m B) 0.498 m C) 2.01 m D) 2.76 m E) none of the above

Question

Quizplus · Accepted Answer

First, we need to calculate the moles of diethyl ether:

m(diethyl ether) = 86.9 g 
M(diethyl ether) = 74.12 g/mol 
n(diethyl ether) = m/M = 1.173 mol

Next, we need to calculate the mass of benzene:

m(benzene) = 425 g

Finally, we can use the definition of molality to calculate the molality of the solution:

molality = moles of solute / mass of solvent (in kg)

mass of solvent = 425 g / 1000 = 0.425 kg

molality = 1.173 mol / 0.425 kg = 2.76 m

Therefore, the answer is D.

What Is the Molality of a Solution Prepared by Dissolving