Analysis of a carbohydrate showed that it consisted of 40.0 % C, 6.71 % H, and 53.3 % O by mass. Its molecular mass was found to be between 140 and 160 amu. What is the molecular formula of this compound?
A) C4H8O6
B) C5H10O5
C) C5H12O5
D) C6H12O4
E) none of the above
Correct Answer:
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