Carbon-14 will emit a $\beta$ particle with an energy of 0.1565 MeV.What is this energy in joules? A)1.0 $\times$ 10^-²⁴ J B)2.5 $\times$ 10^-20 J C)1.0 $\times$ 10^-18 J D)2.5 $\times$ 10^-14 J E)None of these choices is correct.

Question

Quizplus · Accepted Answer

To convert MeV to joules, use the conversion factor: 1 MeV = 1.60218 x 10^-13 J. Thus, 0.1565 MeV = 0.1565 x 1.60218 x 10^-13 J = 2.507 x 10^-14 J, which is approximately 2.5 x 10^-14 J.

Carbon-14 Will Emit A β\betaβ Particle with an Energy of 0 ×\times×

Carbon-14 Will Emit A $\beta$ Particle with an Energy of 0 $\times$