Calculate the solubility of silver chromate, Ag₂CrO₄, in 0.005 M Na₂CrO₄. K_sp = 2.6 * 10¯¹² A) 1.4 * 10¯⁴ M B) 3.4 * 10¯⁵ M C) 1.1 * 10¯⁵ M D) 1.6 * 10¯⁶ M E)

Question

Calculate the solubility of silver chromate, Ag₂CrO₄, in 0.005 M Na₂CrO₄. K_sp = 2.6 * 10¯¹² A) 1.4 * 10¯⁴ M B) 3.4 * 10¯⁵ M C) 1.1 * 10¯⁵ M D) 1.6 * 10¯⁶ M E) < 1.0 * 10¯⁶ M

Quizplus · Accepted Answer

The solubility of Ag₂CrO₄ in a solution containing a common ion (CrO₄²⁻) is calculated using the Ksp expression: Ksp = [Ag⁺]²[CrO₄²⁻]. Given [CrO₄²⁻] = 0.005 M, solve for [Ag⁺]: 2.6 * 10⁻¹² = [Ag⁺]²(0.005), resulting in [Ag⁺] = 1.1 * 10⁻⁵ M.

Calculate the Solubility of Silver Chromate, Ag2CrO4, in 0

Calculate the Solubility of Silver Chromate, Ag₂CrO₄, in 0