How many moles of bromide ions are present in 750.0 mL of 1.35 M MgBr₂? A) 0.506 mol B) 1.01 mol C) 2.03 mol D) 3.04 mol E) None of these choices is correct.

Question

Quizplus · Accepted Answer

To find the number of moles of bromide ions, we need to multiply the volume of the solution (in liters) by the molarity of bromide ions (which is equal to the molarity of MgBr₂ since there is only one MgBr₂ ion and two Br- ions in the compound). Firstly, we need to convert the volume from mL to L: 750.0 mL = 750.0/1000 L = 0.750 L Now, we can calculate the number of moles of Br- ions: moles of Br- = volume (L) x molarity of Br- moles of Br- = 0.750 L x 1.35 mol/L moles of Br- = 1.01 mol Therefore, the answer is choice C (2.03 mol).

How Many Moles of Bromide Ions Are Present in 750