Consider the set of isoelectronic atoms and ions A^2-,B^-,C,D⁺,and E²⁺.Which arrangement of relative radii is correct? A)A^2- B^- C D⁺ E²⁺ B)E²⁺ D⁺ C B^- A^2- C)A^2- B^- C

Question

Consider the set of isoelectronic atoms and ions A^2-,B^-,C,D⁺,and E²⁺.Which arrangement of relative radii is correct? A)A^2- > B^- > C > D⁺ > E²⁺ B)E²⁺ > D⁺ > C > B^- > A^2- C)A^2- > B^- > C < D⁺ < E²⁺ D)A^2- < B^- < C > D⁺ > E²⁺ E)None of these is correct.

Quizplus · Accepted Answer

Isoelectronic species have the same number of electrons, but they can have different numbers of protons, which determines their atomic radius. As the number of protons increases, the atomic radius decreases. Among the given set, we can see that A, B, and E all have the same number of electrons, but A has more protons than B and E. Similarly, D has fewer protons than C. Therefore, the order of increasing atomic radius is: A^2- > B^- > C > D⁺ > E²⁺. Hence, option A is correct.

Consider the Set of Isoelectronic Atoms and Ions A2-,B-,C,D+,and E2+

Consider the Set of Isoelectronic Atoms and Ions A^2-,B^-,C,D⁺,and E²⁺