How many milliliters of 1.58 M HCl are needed to react completely with 23.2 g of NaHCO3 (
= 84.02 g/mol) ?
HCl(aq) + NaHCO3(s) NaCl(s) + H2O(l) + CO2(g)
A) 638 mL
B) 572 mL
C) 536 mL
D) 276 mL
E) 175 mL
Correct Answer:
Verified
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