What is the percent yield for the reaction
PCl3(g) + Cl2(g) PCl5(g)
If 119.3 g of PCl5 (
= 208.2 g/mol) are formed when 61.3 g of Cl2 (
= 70.91 g/mol) react with excess PCl3?
A) 195%
B) 85.0%
C) 66.3%
D) 51.4%
E) 43.7%
Correct Answer:
Verified
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