Factor out the common factor. 35n⁴ + 5n³ + 45n² A) 5(7n⁴ + n³ + 9n²) B) 5n²(7n² + n + 9) C) n²(35n ² + 5n + 45) D) 35n²(n ² + n + 9) E) 35(7n⁴ + n³ + 9n²)

Question

Quizplus · Accepted Answer

The common factor among all terms is $5n^{12}$, and factoring it out correctly results in option B, which simplifies the expression accurately by extracting the common factor and adjusting the powers of $n$ accordingly.

Factor Out the Common Factor