If 11.2 g of naphthalene,C₁₀H₈,is dissolved in 105.4 g of chloroform,CHCl₃,what is the molality of the solution? A) 0.0875 m B) 12.7 m C) 0.830 m D) 0.0961 m E) 0.0991 m

Question

Quizplus · Accepted Answer

First, we need to find the number of moles of naphthalene:

n = m/M

Where m is the mass of naphthalene (11.2 g) and M is the molar mass of naphthalene (128.17 g/mol).

n = 11.2 g / 128.17 g/mol
n = 0.0873 mol

Next, we need to find the mass of chloroform:

m = 105.4 g

We can then calculate the molality using the following equation:

molality = moles of solute / mass of solvent (in kg)

We need to convert the mass of chloroform to kg:

mass of solvent = 105.4 g = 0.1054 kg

Now we can plug in the values:

molality = 0.0873 mol / 0.1054 kg
molality = 0.830 m

Therefore, the molality of the solution is 0.830 m, and the best choice is C.

If 112 G of Naphthalene,C10H8,is Dissolved in 105

If 112 G of Naphthalene,C₁₀H₈,is Dissolved in 105