Balance the following redox reaction if it occurs in H₂SO₄.What are the coefficients in front of C₁₀H₂₂O₂and H₂SO₄ in the balanced reaction? C₁₀H₂₂O₂(aq)+ Na₂Cr₂O₇(aq)→ C₁₀H₁₈O₄(aq)+ Cr₂(SO₄)₃(aq) A) C₁₀H₂₂O₂= 3, H₂SO₄ = 4 B) C₁₀H₂₂O₂= 2, H₂SO₄ = 8 C) C₁₀H₂₂O₂= 1, H₂SO₄ = 16 D) C₁₀H₂₂O₂= 3, H₂SO₄ = 16 E) C₁₀H₂₂O₂= 2, H₂SO₄ = 4

Question

Quizplus · Accepted Answer

To balance the redox reaction, we need to first identify the oxidation state of each element in the reaction. In this case, we have: Cr: +6 to +3 O: -2 to 0 S: +6 to -2 C: +4 to +3 H: +1 to 0 Na: +1 to +2 To balance the reaction, we begin by balancing the number of atoms of each element. Then we must balance the charges with electrons. Finally, we add the two half-reactions together and cancel out any terms that appear on both sides of the equation. The balanced equation is: 3 C₁₀H₂₂O₂(aq) + 8 Na₂Cr₂O₇(aq) → 3 C₁₀H₁₈O₄(aq) + 2 Cr(SO₄)₃(aq) Therefore, the coefficients in front of C₁₀H₂₂O₂ and H₂SO₄ are 3 and 16, respectively. The best choice is D because it is the only option with the correct coefficients for both of these species.

Balance the Following Redox Reaction If It Occurs in H2SO4

Balance the Following Redox Reaction If It Occurs in H₂SO₄