Determine the pH of a 0.00598 M HClO₄ solution. A) 11.777 B) 6.434 C) 7.566 D) 2.223 E) 3.558

Question

Quizplus · Accepted Answer

HClO is a weak acid, and therefore it undergoes partial dissociation in water according to the equation: 
HClO ⇌ H+ + ClO-
The acid dissociation constant for HClO is Ka = 3.5 x 10^-8. Using this value and the initial concentration of HClO, we can calculate the concentration of H+ ions in the solution:
Ka = [H+][ClO-]/[HClO]
3.5 x 10^-8 = [H+]^2 / 0.00598
[H+] = 1.88 x 10^-4 M
pH = -log[H+] = 3.74
Therefore, the correct answer is D) 2.223

Determine the PH of a 0