When 1.00 mol of benzene is vaporized at a constant pressure of 1.00 atm and at its normal boiling point of 80.1°C,33.9 kJ are absorbed and PΔV for the vaporization process is equal to 2.90 kJ,then
A) ΔE = 31.0 kJ and ΔH = 33.9 kJ.
B) ΔE = 36.8 kJ and ΔH = 33.9 kJ.
C) ΔE = 33.9 kJ and ΔH = 31.0 kJ.
D) ΔE = 33.9 kJ and ΔH = 36.8 kJ.