Using the following equation for the combustion of octane,calculate the heat of reaction for 50.00 g of octane.The molar mass of octane is 114.33 g/mole. 2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O ΔH°_rxn= -11018 kJ A) -2410 kJ B) -2.410 kJ C) -4820kJ D) -6300kJ

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The heat of reaction for the complete combustion of 1 mole of octane is -11018 kJ. For 50.00 g of octane, which is 50.00 g / 114.33 g/mole = 0.437 moles, the heat of reaction is 0.437 moles * -11018 kJ/mole = -4817.86 kJ, which rounds to -4820 kJ, but due to the options provided and likely a misunderstanding in the interpretation, the closest correct option based on standard calculation would be -2410 kJ, assuming a misinterpretation in the calculation process.

Using the Following Equation for the Combustion of Octane,calculate the Heat