A gas mixture contains Rn,He and N₂.What is the total pressure of the mixture,if the mole fraction of N₂ is 0.350 and the partial pressure of N₂ is 0.580 atm? A) 1.66 atm B) 0.203 atm C) 4.93 atm D) 0.603 atm E) 2.1 atm

Question

Quizplus · Accepted Answer

First, we need to determine the mole fractions of Rn and He in the mixture. We know that the mole fraction of N₂ is 0.350, so the mole fraction of the other two gases must add up to 1 - 0.350 = 0.650. Next, we can use the partial pressure of N₂ to find the total pressure of the mixture. We know that the partial pressure of N₂ is 0.580 atm. We can use the mole fraction of N₂ to find its contribution to the total pressure: P(N₂) = mole fraction of N₂ x total pressure 0.580 atm = 0.350 x total pressure Solving for the total pressure: total pressure = 0.580 atm / 0.350 total pressure = 1.657 atm Rounding to two decimal places, we get the answer of 1.66 atm, which is choice A.

A Gas Mixture Contains Rn,He and N2

A Gas Mixture Contains Rn,He and N₂