What is the oxidation number of the chromium atom in H₂CrO₄? A) +2 B) +4 C) +6 D) -7 E) -3

Question

Quizplus · Accepted Answer

To determine the oxidation state of the Cr atom, we need to consider the other atoms in the compound and their known oxidation states. H = +1 S = -2 O = -2 Let x be the oxidation state of Cr Therefore, (+1) + (-2) + (x) + (-2) + (-1) + (+4) + (-2) + (-1) + (+4) + (-2) = 0 Simplifying the equation gives: x = +6 Thus, the oxidation number of the chromium atom in H₂CrO₄ is +6.

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What Is the Oxidation Number of the Chromium Atom in H₂CrO₄