Lithium and nitrogen react in a combination reaction to produce lithium nitride: 6 Li(s) + (g) → 2 Li₃N(s)
How many moles of lithium are needed to produce 0.31 mol of N when the reaction is carried out in the presence of excess nitrogen?

Question

Lithium and nitrogen react in a combination reaction to produce lithium nitride: 6 Li(s) +

(g) → 2 Li₃N(s)
How many moles of lithium are needed to produce 0.31 mol of Lithium and nitrogen react in a combination reaction to produce lithium nitride: 6 Li(s) + (g) → 2 Li<sub>3</sub>N(s) How many moles of lithium are needed to produce 0.31 mol of N when the reaction is carried out in the presence of excess nitrogen? A) 0.16 B) 0.93 C) 0.10 D) 0.21 E) 1.9

N when the reaction is carried out in the presence of excess nitrogen?

Quizplus · Accepted Answer

The Answer of Lithium and nitrogen react in a combination reaction to produce lithium nitride: 6 Li(s)+ (g)→ 2 Li₃N(s) How many moles of lithium are needed to produce 0.31 mol of N when the reaction is carried out in the presence of excess nitrogen? A) 0.16 B) 0.93 C) 0.10 D) 0.21 E) 1.9

Lithium and Nitrogen React in a Combination Reaction to Produce