Lithium and nitrogen react to produce lithium nitride: 6 Li(s) + (g) → 2 Li₃N(s)
How many moles of are needed to react with 0.550 mol of lithium?

Question

Lithium and nitrogen react to produce lithium nitride: 6 Li(s)+ (g)→ 2 Li₃N(s) How many moles of are needed to react with 0.550 mol of lithium? A) 3.30 B) 0.550 C) 0.183 D) 1.65 E) 0.0917

Quizplus · Accepted Answer

The Answer of Lithium and nitrogen react to produce lithium nitride: 6 Li(s)+ (g)→ 2 Li₃N(s) How many moles of are needed to react with 0.550 mol of lithium? A) 3.30 B) 0.550 C) 0.183 D) 1.65 E) 0.0917

Lithium and Nitrogen React to Produce Lithium Nitride: 6 Li(s)