If x is a normal random variable with mean 80 and standard deviation 5,the z score for x = 88 is ___.
A)1.8
B)-1.8
C)1.6
D)-1.6
E)8.0

Name: If x is a normal random variable with mean 80 and standard deviation 5,the z score for x = 88 is ___. A)1.8 B)-1.8 C)1.6 D)-1.6 E)8.0
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Question

Quizplus · Accepted Answer

To find the z-score for x = 88, we use the formula:

z = (x - μ) / σ

where x is the given value (88), μ is the mean (80), and σ is the standard deviation (5).

So,

z = (88 - 80) / 5 = 1.6

Therefore, the z-score for x = 88 is 1.6.

If X Is a Normal Random Variable with Mean 80