Consider the following reaction: Ni(CO)₄(g) → Ni(s)+ 4CO(g) If the initial concentration of Ni(CO)₄(g)is 1.0 M,and x is the equilibrium concentration of CO(g),what is the correct equilibrium relation?

Question

Quizplus · Accepted Answer

The equilibrium constant expression for the given reaction is: K_c = [Ni(s)][CO]4 /[Ni(CO)₄] At equilibrium, the concentration of Ni(CO)₄ will decrease by x, and the concentration of CO will increase by 4x. Therefore, the equilibrium expression becomes: K_c = [Ni(s)][(1.0 + 4x)]4 /[(1.0 - x)] Simplifying, K_c = [Ni(s)][1.0 + 4x]4 / [1.0 - x] So, the correct equilibrium relation is given in Choice C.

Consider the Following Reaction: Ni(CO)4(g) → Ni(s)+ 4CO(g)

Consider the Following Reaction: Ni(CO)₄(g) → Ni(s)+ 4CO(g)