Calculate $\Delta$S_surr° at 298 K for the reaction 6C(s)+ 3H₂(g)$\rightarrow$ C₆H₆(l) $\Delta$H_r° = +49.0 J.K^-1.mol^-1,$\Delta$S_r° = -253 J.K^-1.mol^-1 A)+164 J.K^-1.mol^-1 B)(-417 J.K^-1.mol^-1) C)+253 J.K^-1.mol^-1 D)(-164 J.K^-1.mol^-1) E)(-253 J.K^-1.mol^-1)

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Quizplus · Accepted Answer

$\Delta$S_surr° = -$\Delta$H_r°/T = -49.0 J.K^-1.mol^-1 / 298 K = -0.164 J.K^-1.mol^-1 ≈ -164 J.K^-1.mol^-1.

Calculate Δ\DeltaΔ Ssurr° at 298 K for the Reaction 6C(s)+ 3H2(g) →\rightarrow→

Calculate $\Delta$ S_surr° at 298 K for the Reaction 6C(s)+ 3H₂(g) $\rightarrow$