Calculate $\Delta$S_surr° at 298 K for the reaction H₂(g)+ F₂(g)$\rightarrow$ 2HF(g) $\Delta$H_r° = -546 kJ.mol^-1,$\Delta$S_r° = +14.1 J.K^-1.mol^-1 A)+14.1 J.K^-1.mol^-1 B)+1820 J.K^-1.mol^-1 C)+1830 J.K^-1.mol^-1 D)(-1830 J.K^-1.mol^-1) E)(-14.1 J.K^-1.mol^-1)

Question

Quizplus · Accepted Answer

$\Delta$S_surr° = - $\Delta$H_r° / T = - (-546 kJ.mol^-1) / 298 K = +1830 J.K^-1.mol^-1

Calculate Δ\DeltaΔ Ssurr° at 298 K for the Reaction H2(g)+ F2(g) →\rightarrow→

Calculate $\Delta$ S_surr° at 298 K for the Reaction H₂(g)+ F₂(g) $\rightarrow$