Calculate the density of camphor,C₁₀H₁₆O,at 80 $\circ$ C and 12 Torr. A)8.2 * 10^-⁴ g.L^-¹ B)0.083 g.L^-¹ C)0.37 g.L^-¹ D)0.62 g.L^-¹ E)6.8 * 10^-3 g.L^-¹

Question

Quizplus · Accepted Answer

To calculate density, we need to use the ideal gas law, PV = nRT. P = 12 Torr = 0.01572 atm T = 80°F = 300.15 K R = 0.08206 L atm/mol K (gas constant) Now we need to find the number of moles of camphor. molecular weight of camphor (C₁₀H₁₆O) = 152 g/mol Density = (molecular weight/RT) x P = (152/0.08206 x 300.15) x 0.01572 = 0.0828 g/cm^3 or 0.083 g/mL (since 1 cm^3 = 1 mL) Therefore, the correct answer is B.

Calculate the Density of Camphor,C10H16O,at 80 ∘\circ∘ C and 12 Torr

Calculate the Density of Camphor,C₁₀H₁₆O,at 80^$\circ$C and 12 Torr